Integrand size = 24, antiderivative size = 160 \[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=-\frac {d (b c-3 a d) \sqrt {c+d x^2}}{2 a b^2}+\frac {(b c-a d) \left (c+d x^2\right )^{3/2}}{2 a b \left (a+b x^2\right )}-\frac {c^{5/2} \text {arctanh}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{a^2}+\frac {(b c-a d)^{3/2} (2 b c+3 a d) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{2 a^2 b^{5/2}} \]
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Time = 0.16 (sec) , antiderivative size = 160, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {457, 100, 159, 162, 65, 214} \[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=\frac {(b c-a d)^{3/2} (3 a d+2 b c) \text {arctanh}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{2 a^2 b^{5/2}}-\frac {c^{5/2} \text {arctanh}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{a^2}-\frac {d \sqrt {c+d x^2} (b c-3 a d)}{2 a b^2}+\frac {\left (c+d x^2\right )^{3/2} (b c-a d)}{2 a b \left (a+b x^2\right )} \]
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Rule 65
Rule 100
Rule 159
Rule 162
Rule 214
Rule 457
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {(c+d x)^{5/2}}{x (a+b x)^2} \, dx,x,x^2\right ) \\ & = \frac {(b c-a d) \left (c+d x^2\right )^{3/2}}{2 a b \left (a+b x^2\right )}+\frac {\text {Subst}\left (\int \frac {\sqrt {c+d x} \left (b c^2-\frac {1}{2} d (b c-3 a d) x\right )}{x (a+b x)} \, dx,x,x^2\right )}{2 a b} \\ & = -\frac {d (b c-3 a d) \sqrt {c+d x^2}}{2 a b^2}+\frac {(b c-a d) \left (c+d x^2\right )^{3/2}}{2 a b \left (a+b x^2\right )}+\frac {\text {Subst}\left (\int \frac {\frac {b^2 c^3}{2}+\frac {1}{4} d \left (b^2 c^2+4 a b c d-3 a^2 d^2\right ) x}{x (a+b x) \sqrt {c+d x}} \, dx,x,x^2\right )}{a b^2} \\ & = -\frac {d (b c-3 a d) \sqrt {c+d x^2}}{2 a b^2}+\frac {(b c-a d) \left (c+d x^2\right )^{3/2}}{2 a b \left (a+b x^2\right )}+\frac {c^3 \text {Subst}\left (\int \frac {1}{x \sqrt {c+d x}} \, dx,x,x^2\right )}{2 a^2}-\frac {\left ((b c-a d)^2 (2 b c+3 a d)\right ) \text {Subst}\left (\int \frac {1}{(a+b x) \sqrt {c+d x}} \, dx,x,x^2\right )}{4 a^2 b^2} \\ & = -\frac {d (b c-3 a d) \sqrt {c+d x^2}}{2 a b^2}+\frac {(b c-a d) \left (c+d x^2\right )^{3/2}}{2 a b \left (a+b x^2\right )}+\frac {c^3 \text {Subst}\left (\int \frac {1}{-\frac {c}{d}+\frac {x^2}{d}} \, dx,x,\sqrt {c+d x^2}\right )}{a^2 d}-\frac {\left ((b c-a d)^2 (2 b c+3 a d)\right ) \text {Subst}\left (\int \frac {1}{a-\frac {b c}{d}+\frac {b x^2}{d}} \, dx,x,\sqrt {c+d x^2}\right )}{2 a^2 b^2 d} \\ & = -\frac {d (b c-3 a d) \sqrt {c+d x^2}}{2 a b^2}+\frac {(b c-a d) \left (c+d x^2\right )^{3/2}}{2 a b \left (a+b x^2\right )}-\frac {c^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{a^2}+\frac {(b c-a d)^{3/2} (2 b c+3 a d) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {b c-a d}}\right )}{2 a^2 b^{5/2}} \\ \end{align*}
Time = 0.35 (sec) , antiderivative size = 146, normalized size of antiderivative = 0.91 \[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=\frac {\frac {a \sqrt {c+d x^2} \left (b^2 c^2+3 a^2 d^2+2 a b d \left (-c+d x^2\right )\right )}{b^2 \left (a+b x^2\right )}-\frac {(-b c+a d)^{3/2} (2 b c+3 a d) \arctan \left (\frac {\sqrt {b} \sqrt {c+d x^2}}{\sqrt {-b c+a d}}\right )}{b^{5/2}}-2 c^{5/2} \text {arctanh}\left (\frac {\sqrt {c+d x^2}}{\sqrt {c}}\right )}{2 a^2} \]
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Time = 3.12 (sec) , antiderivative size = 165, normalized size of antiderivative = 1.03
method | result | size |
pseudoelliptic | \(\frac {-\frac {3 \left (b \,x^{2}+a \right ) \left (a d +\frac {2 b c}{3}\right ) \left (a d -b c \right )^{2} \arctan \left (\frac {b \sqrt {d \,x^{2}+c}}{\sqrt {\left (a d -b c \right ) b}}\right )}{2}+\frac {3 \left (-\frac {2 b^{2} c^{\frac {5}{2}} \left (b \,x^{2}+a \right ) \operatorname {arctanh}\left (\frac {\sqrt {d \,x^{2}+c}}{\sqrt {c}}\right )}{3}+\left (\frac {b^{2} c^{2}}{3}-\frac {2 a d \left (-d \,x^{2}+c \right ) b}{3}+a^{2} d^{2}\right ) a \sqrt {d \,x^{2}+c}\right ) \sqrt {\left (a d -b c \right ) b}}{2}}{b^{2} \left (b \,x^{2}+a \right ) a^{2} \sqrt {\left (a d -b c \right ) b}}\) | \(165\) |
default | \(\text {Expression too large to display}\) | \(5354\) |
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Time = 1.02 (sec) , antiderivative size = 1132, normalized size of antiderivative = 7.08 \[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=\left [-\frac {{\left (2 \, a b^{2} c^{2} + a^{2} b c d - 3 \, a^{3} d^{2} + {\left (2 \, b^{3} c^{2} + a b^{2} c d - 3 \, a^{2} b d^{2}\right )} x^{2}\right )} \sqrt {\frac {b c - a d}{b}} \log \left (\frac {b^{2} d^{2} x^{4} + 8 \, b^{2} c^{2} - 8 \, a b c d + a^{2} d^{2} + 2 \, {\left (4 \, b^{2} c d - 3 \, a b d^{2}\right )} x^{2} - 4 \, {\left (b^{2} d x^{2} + 2 \, b^{2} c - a b d\right )} \sqrt {d x^{2} + c} \sqrt {\frac {b c - a d}{b}}}{b^{2} x^{4} + 2 \, a b x^{2} + a^{2}}\right ) - 4 \, {\left (b^{3} c^{2} x^{2} + a b^{2} c^{2}\right )} \sqrt {c} \log \left (-\frac {d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {c} + 2 \, c}{x^{2}}\right ) - 4 \, {\left (2 \, a^{2} b d^{2} x^{2} + a b^{2} c^{2} - 2 \, a^{2} b c d + 3 \, a^{3} d^{2}\right )} \sqrt {d x^{2} + c}}{8 \, {\left (a^{2} b^{3} x^{2} + a^{3} b^{2}\right )}}, \frac {8 \, {\left (b^{3} c^{2} x^{2} + a b^{2} c^{2}\right )} \sqrt {-c} \arctan \left (\frac {\sqrt {-c}}{\sqrt {d x^{2} + c}}\right ) - {\left (2 \, a b^{2} c^{2} + a^{2} b c d - 3 \, a^{3} d^{2} + {\left (2 \, b^{3} c^{2} + a b^{2} c d - 3 \, a^{2} b d^{2}\right )} x^{2}\right )} \sqrt {\frac {b c - a d}{b}} \log \left (\frac {b^{2} d^{2} x^{4} + 8 \, b^{2} c^{2} - 8 \, a b c d + a^{2} d^{2} + 2 \, {\left (4 \, b^{2} c d - 3 \, a b d^{2}\right )} x^{2} - 4 \, {\left (b^{2} d x^{2} + 2 \, b^{2} c - a b d\right )} \sqrt {d x^{2} + c} \sqrt {\frac {b c - a d}{b}}}{b^{2} x^{4} + 2 \, a b x^{2} + a^{2}}\right ) + 4 \, {\left (2 \, a^{2} b d^{2} x^{2} + a b^{2} c^{2} - 2 \, a^{2} b c d + 3 \, a^{3} d^{2}\right )} \sqrt {d x^{2} + c}}{8 \, {\left (a^{2} b^{3} x^{2} + a^{3} b^{2}\right )}}, \frac {{\left (2 \, a b^{2} c^{2} + a^{2} b c d - 3 \, a^{3} d^{2} + {\left (2 \, b^{3} c^{2} + a b^{2} c d - 3 \, a^{2} b d^{2}\right )} x^{2}\right )} \sqrt {-\frac {b c - a d}{b}} \arctan \left (-\frac {{\left (b d x^{2} + 2 \, b c - a d\right )} \sqrt {d x^{2} + c} \sqrt {-\frac {b c - a d}{b}}}{2 \, {\left (b c^{2} - a c d + {\left (b c d - a d^{2}\right )} x^{2}\right )}}\right ) + 2 \, {\left (b^{3} c^{2} x^{2} + a b^{2} c^{2}\right )} \sqrt {c} \log \left (-\frac {d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {c} + 2 \, c}{x^{2}}\right ) + 2 \, {\left (2 \, a^{2} b d^{2} x^{2} + a b^{2} c^{2} - 2 \, a^{2} b c d + 3 \, a^{3} d^{2}\right )} \sqrt {d x^{2} + c}}{4 \, {\left (a^{2} b^{3} x^{2} + a^{3} b^{2}\right )}}, \frac {{\left (2 \, a b^{2} c^{2} + a^{2} b c d - 3 \, a^{3} d^{2} + {\left (2 \, b^{3} c^{2} + a b^{2} c d - 3 \, a^{2} b d^{2}\right )} x^{2}\right )} \sqrt {-\frac {b c - a d}{b}} \arctan \left (-\frac {{\left (b d x^{2} + 2 \, b c - a d\right )} \sqrt {d x^{2} + c} \sqrt {-\frac {b c - a d}{b}}}{2 \, {\left (b c^{2} - a c d + {\left (b c d - a d^{2}\right )} x^{2}\right )}}\right ) + 4 \, {\left (b^{3} c^{2} x^{2} + a b^{2} c^{2}\right )} \sqrt {-c} \arctan \left (\frac {\sqrt {-c}}{\sqrt {d x^{2} + c}}\right ) + 2 \, {\left (2 \, a^{2} b d^{2} x^{2} + a b^{2} c^{2} - 2 \, a^{2} b c d + 3 \, a^{3} d^{2}\right )} \sqrt {d x^{2} + c}}{4 \, {\left (a^{2} b^{3} x^{2} + a^{3} b^{2}\right )}}\right ] \]
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\[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=\int \frac {\left (c + d x^{2}\right )^{\frac {5}{2}}}{x \left (a + b x^{2}\right )^{2}}\, dx \]
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\[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=\int { \frac {{\left (d x^{2} + c\right )}^{\frac {5}{2}}}{{\left (b x^{2} + a\right )}^{2} x} \,d x } \]
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Time = 0.30 (sec) , antiderivative size = 206, normalized size of antiderivative = 1.29 \[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=\frac {c^{3} \arctan \left (\frac {\sqrt {d x^{2} + c}}{\sqrt {-c}}\right )}{a^{2} \sqrt {-c}} + \frac {\sqrt {d x^{2} + c} d^{2}}{b^{2}} - \frac {{\left (2 \, b^{3} c^{3} - a b^{2} c^{2} d - 4 \, a^{2} b c d^{2} + 3 \, a^{3} d^{3}\right )} \arctan \left (\frac {\sqrt {d x^{2} + c} b}{\sqrt {-b^{2} c + a b d}}\right )}{2 \, \sqrt {-b^{2} c + a b d} a^{2} b^{2}} + \frac {\sqrt {d x^{2} + c} b^{2} c^{2} d - 2 \, \sqrt {d x^{2} + c} a b c d^{2} + \sqrt {d x^{2} + c} a^{2} d^{3}}{2 \, {\left ({\left (d x^{2} + c\right )} b - b c + a d\right )} a b^{2}} \]
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Time = 6.38 (sec) , antiderivative size = 1321, normalized size of antiderivative = 8.26 \[ \int \frac {\left (c+d x^2\right )^{5/2}}{x \left (a+b x^2\right )^2} \, dx=\text {Too large to display} \]
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